Searched refs:LZMAFile (Results 1 - 4 of 4) sorted by relevance
/third_party/python/Lib/test/ |
H A D | test_lzma.py | 19 from lzma import LZMACompressor, LZMADecompressor, LZMAError, LZMAFile namespace 537 with LZMAFile(BytesIO(COMPRESSED_XZ)) as f: 539 with LZMAFile(BytesIO(), "w") as f: 541 with LZMAFile(BytesIO(), "x") as f: 543 with LZMAFile(BytesIO(), "a") as f: 549 with LZMAFile(filename) as f: 551 with LZMAFile(filename, "a") as f: 553 with LZMAFile(filename) as f: 558 with LZMAFile(TESTFN) as f: 560 with LZMAFile(TESTF [all...] |
H A D | test_tarfile.py | 88 open = lzma.LZMAFile if lzma else None 775 self.skipTest("LZMAFile have no name attribute")
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/third_party/python/Lib/ |
H A D | lzma.py | 20 "LZMACompressor", "LZMADecompressor", "LZMAFile", "LZMAError", 38 class LZMAFile(_compression.BaseStream): class 42 An LZMAFile can act as a wrapper for an existing file object, or 45 Note that LZMAFile provides a *binary* file interface - data read 286 LZMAFile. 288 For binary mode, this function is equivalent to the LZMAFile 289 constructor: LZMAFile(filename, mode, ...). In this case, the 292 For text mode, an LZMAFile object is created, and wrapped in an 309 binary_file = LZMAFile(filename, lz_mode, format=format, check=check,
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H A D | tarfile.py | 1948 from lzma import LZMAFile, LZMAError namespace 1952 fileobj = LZMAFile(fileobj or name, mode, preset=preset)
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