Lines Matching refs:kMaxObjects
45 static const int kMaxObjects = 4 * (1 << 10);
46 T* objs[kMaxObjects];
49 for (int j = 0; j < kMaxObjects; ++j) {
53 for (int j = kMaxObjects - 1; j >= 0; --j) {
69 static const int kMaxObjects = 4 * (1 << 10);
70 T* objs[kMaxObjects];
73 for (int j = 0; j < kMaxObjects; ++j) {
77 for (int j = 0; j < kMaxObjects; ++j) {
93 static const int kMaxObjects = 4 * (1 << 10);
94 T* objs[kMaxObjects];
97 for (int j = 0; j < kMaxObjects; ++j) {
114 static const int kMaxObjects = 4 * (1 << 10);
115 T* objs[kMaxObjects];
116 for (int i = 0; i < kMaxObjects; ++i) {
132 // Execute 2*kMaxObjects operations, which should average to N create and N destroy,
134 for (int j = 0; j < 2 * kMaxObjects; ++j) {
135 int k = r.nextRangeU(0, kMaxObjects-1);
145 for (int j = 0; j < kMaxObjects; ++j) {