Lines Matching defs:start
235 the start and one at the end of the string. Now skip the
236 two at the start. */
313 const char *start = expr_start + 1;
314 while (start && *start != '}' && *start != '\n') {
315 if (*start != ' ' && *start != '\t' && *start != '\f') {
319 start++;
325 start = expr_start;
326 while (start > parent_str && *start != '\n') {
327 start--;
329 *p_cols += (int)(expr_start - start);
330 if (*start == '\n') {
334 /* adjust the start based on the number of newlines encountered
501 /* Where a single '{' is the start of a new expression, a
904 /* We must now be the start of an expression, on a '{'. */
941 /* Until we start allocating dynamically, p points to data. */