Lines Matching defs:prev_idx
53 int prev_idx; ///< pointer to the previous path point
77 path[0][cb].prev_idx = -1;
89 path[swb+1][0].prev_idx = next_mincb;
93 path[swb+1][0].prev_idx = 0;
101 path[swb+1][cb].prev_idx = -1;
113 path[swb+1][cb].prev_idx = -1;
121 path[swb+1][cb].prev_idx = -1;
138 path[swb+1][cb].prev_idx = mincb;
142 path[swb+1][cb].prev_idx = cb;
167 idx = path[ppos-path[ppos][cb].run+1][cb].prev_idx;