Lines Matching defs:byte
2314 * If the guest has 4-byte PTEs then that means it's using 32-bit,
2316 * (i.e. 8-byte PTEs). The difference in PTE size means that KVM must
2329 * Concretely, a 4-byte PDE consumes bits 31:22, while an 8-byte PDE
2332 * quadrant is assigned in mmu_alloc_root(). A 4-byte PTE consumes
2333 * bits 21:12, while an 8-byte PTE consumes bits 20:12. To consume
2335 * quadrant, i.e. sets quadrant to '0' or '1'. The parent 8-byte PDE
4947 unsigned byte;
4958 for (byte = 0; byte < ARRAY_SIZE(mmu->permissions); ++byte) {
4959 unsigned pfec = byte << 1;
5013 mmu->permissions[byte] = ff | uf | wf | smepf | smapf;