Lines Matching refs:LOG
255 |--ENTRY POINT FOR LOG(X) FOR DENORMALIZED INPUT
318 |--ENTRY POINT FOR LOG(X) FOR X FINITE, NON-ZERO, NOT NAN'S
335 blt LOGNEG | ...LOG OF NEGATIVE ARGUMENT IS INVALID
344 |--THE IDEA IS THAT LOG(X) = K*LOG2 + LOG(Y)
345 |-- = K*LOG2 + LOG(F) + LOG(1 + (Y-F)/F).
347 |--LOG(1+U) CAN BE VERY EFFICIENT.
356 lea LOGTBL,%a0 | ...BASE ADDRESS OF 1/F AND LOG(F)
387 |--LOG(1+U) IS APPROXIMATED BY
407 addal #16,%a0 | ...ADDRESS OF LOG(F)
413 faddx (%a0),%fp1 | ...LOG(F)+U*V*(A2+V*(A4+V*A6))
415 faddx %fp1,%fp0 | ...FP0 IS LOG(F) + LOG(1+U)
428 |--LOG(X) = LOG(1+U/2)-LOG(1-U/2) WHICH IS AN ODD POLYNOMIAL
472 |--REGISTERS SAVED FPCR. LOG(-VE) IS INVALID
477 |--ENTRY POINT FOR LOG(1+Z) FOR DENORMALIZED INPUT
484 |--ENTRY POINT FOR LOG(1+X) FOR X FINITE, NON-ZERO, NOT NAN'S
504 ble LP1NEG0 | ...LOG OF ZERO OR -VE
509 |--SIMPLY INVOKE LOG(X) FOR LOG(1+Z).
517 |--EXP(-1/16) < X < EXP(1/16). LOG(1+Z) = LOG(1+U/2) - LOG(1-U/2)